A) 7.412
B) 8.412
C) 9.412
D) 10.412
Correct Answer: C
Solution :
[c] \[{{H}_{2}}S{{O}_{4}}\] is 95% by volume, so |
wt. of \[{{H}_{2}}S{{O}_{4}}=95\,g\] |
Vol. of solution = 100 ml |
\[\therefore \] Moles of \[{{H}_{2}}S{{O}_{4}}=\frac{95}{98}.\] |
And weight of solution \[=100\times 1.98=198\text{ }g\] |
Weight of water \[=198-95=103\text{ }g\] |
Molality \[=\frac{95\times 1000}{98\times 103}=9.412\] |
Hence, molality of \[{{H}_{2}}S{{O}_{4}}\] solution is 9.412. |
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