A) Lower osmotic pressure
B) Same osmotic pressure
C) Higher osmotic pressure
D) None of these
Correct Answer: B
Solution :
[b] \[{{M}_{\text{total}}}=\frac{({{n}_{1}}+{{n}_{2}})}{{{v}_{1}}+{{v}_{2}}}st,\] |
\[{{n}_{1}}={{n}_{2}}=0,1,{{V}_{1}}={{V}_{2}}=1\] |
litre \[\Rightarrow \]\[{{M}_{\text{total}}}=0.1M\] |
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