List (I) | List (II) |
[A] 50 mL of 3M HCl solution +150 mL of 1 M \[FeC{{l}_{3}}\] solution | (p) 4.17 m |
[B] An aqueous solution of NaCl with mole fraction of NaCl as 0.1 | (q) \[[C{{l}^{-}}]=3M\] |
[C] 20% (w/w) propanol \[({{C}_{3}}{{H}_{7}}OH)\] solution | (r) \[[{{H}^{+}}]=2.75M\] |
[D] 10.95% (w/v) HCl solution | (s) 6.1 m |
A) A-r, B-s, C-p, D-q
B) A-q, B-s, C-r, D-q
C) A-q, B-s, C-p, D-q
D) A-q, B-r, C-p, D-s
Correct Answer: C
Solution :
[c] |
[a] \[[C{{l}^{-}}]=\frac{50\times 3+150\times 1\times 3}{200}=\frac{600}{200}=3M\] |
[b] Molality \[=\frac{0.1}{0.9\times 18}\times 1000=6.17\,m\] |
[c] Molality \[=\frac{10\times 1000}{60\times 90}=1.85\,m\] |
[d] Molarity of \[HCl=\frac{\frac{10.95}{36.5}}{100}\times 1000=3M\] |
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