s
A) 28 g
B) 20 g
C) 40 g
D) 23 g
Correct Answer: C
Solution :
| [c] We know that, one mole of an element \[=6.02\times {{10}^{23}}\] atoms |
| = Atomic weight of the element |
| Now, \[1.58\times {{10}^{22}}\] atoms weigh 1.05 g |
| \[\therefore \] \[6.02\times {{10}^{23}}\] atoms weigh |
| \[=\frac{(1.05\times 6.02\times {{10}^{23}})}{1.58\times {{10}^{22}}}\] |
| = 40 g |
| Atomic weight of \[X=40g\] |
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