A) 104.4 kg
B) 105.4 kg
C) 212.8 kg
D) 106.4 kg
Correct Answer: D
Solution :
| [d] \[\because \] 100 kg impure sample has pure \[CaC{{O}_{3}}\] |
| = 95 kg |
| \[\therefore \] 200 kg impure sample has pure \[CaC{{O}_{3}}\] |
| \[=\frac{95\times 200}{100}=190\,kg\] |
| \[CaC{{O}_{3}}\to CaO+C{{O}_{2}}\] |
| \[\because \] 100 kg \[CaC{{O}_{3}}\] gives \[CaO=56\,kg\]. |
| \[\therefore \] 190 kg \[CaC{{O}_{3}}\] gives |
| \[CaO=\frac{56\times 190}{100}=106.4\,kg\]. |
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