A) + 1 or - 1
B) + 2 or - 2
C) + 2.5 or - 2.5
D) + 3 or - 3
Correct Answer: C
Solution :
[c] Total spin = Number of unpaired \[{{e}^{-}}\times \left( \pm \frac{1}{2} \right)\] |
\[=5\times \left( \pm \frac{1}{2} \right)=\pm \frac{5}{2}\] |
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