A) 600 K
B) 750 K
C) 450 K
D) 900 K
Correct Answer: B
Solution :
[b]\[\frac{W}{{{Q}_{1}}+W}={{\eta }_{1}}\] \[\frac{W}{{{Q}_{1}}}={{\eta }_{2}}\] |
\[\frac{W}{{{Q}_{1}}}=1-\frac{300}{T}\] |
\[\Rightarrow \] \[\frac{1}{1+\frac{T}{T-300}}=\frac{1200-T}{1200}\] |
\[\Rightarrow \]\[(T-300)1200=(1200-T)(2T-300)\] |
\[T=750K\] |
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