A) \[320{}^\circ C\]
B) \[39{}^\circ C\]
C) 325 K
D) \[325{}^\circ C\]
Correct Answer: B
Solution :
| [b]Given \[\beta =5\] |
| We have, \[\beta =\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}\] |
| where \[{{T}_{1}}=\] temp. of surrounding, |
| \[{{T}_{2}}=\] temp. of cold body |
| \[=-{{13}^{0}}C=(-13+273)K=260K\] |
| or \[5=\frac{260}{{{T}_{1}}-260}\] |
| \[5{{T}_{1}}=260+1300\] or \[{{T}_{1}}=312\,K={{39}^{o}}C\]. |
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