• # question_answer The degrees of freedom per molecule of an ideal gas is 5. Work done by the gas is 100 J when it expands isobarically. The heat absorbed by the gas will be A) 250 J B) 150 J C) 350 J D) 200 J

 [c] Degrees of freedom is 5 Hence ${{C}_{V}}=\frac{5}{2}RT$ and ${{C}_{P}}=\frac{7}{2}RT$ $\frac{dQ}{dU}=\frac{n{{C}_{P}}dT}{n{{C}_{V}}dT}=\frac{{{C}_{P}}}{{{C}_{V}}}$ or         $\frac{dQ}{dQ-dW}=\frac{7}{5}$ $\therefore$    $dQ=3.5dW=3.5(100)$ $=350\text{ }J$