A) 250 J
B) 150 J
C) 350 J
D) 200 J
Correct Answer: C
Solution :
| [c] Degrees of freedom is 5 |
| Hence \[{{C}_{V}}=\frac{5}{2}RT\] and \[{{C}_{P}}=\frac{7}{2}RT\] |
| \[\frac{dQ}{dU}=\frac{n{{C}_{P}}dT}{n{{C}_{V}}dT}=\frac{{{C}_{P}}}{{{C}_{V}}}\] |
| or \[\frac{dQ}{dQ-dW}=\frac{7}{5}\] |
| \[\therefore \] \[dQ=3.5dW=3.5(100)\] |
| \[=350\text{ }J\] |
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