JEE Main & Advanced Physics Thermodynamical Processes Sample Paper Topic Test - Thermodynamical Processes

  • question_answer
    The degrees of freedom per molecule of an ideal gas is 5. Work done by the gas is 100 J when it expands isobarically. The heat absorbed by the gas will be

    A) 250 J

    B) 150 J

    C) 350 J

    D) 200 J

    Correct Answer: C

    Solution :

    [c] Degrees of freedom is 5
                Hence \[{{C}_{V}}=\frac{5}{2}RT\] and \[{{C}_{P}}=\frac{7}{2}RT\]
                or         \[\frac{dQ}{dQ-dW}=\frac{7}{5}\]
                \[\therefore \]    \[dQ=3.5dW=3.5(100)\]
                            \[=350\text{ }J\]

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