• question_answer For a cyclic process $A\to B\to C\to A,$ the following information is given Path $\Delta Q$(Heat supplied) $\Delta U$ (Increase in internal energy) Work done by system on surrounding $A\to B$ 600 J 200 J 400 J $B\to C$ - 100 J 100 J - 200 J $C\to A$ - 100 J - 300 J 200 J Calculate the heat of the cycle and efficiency of cycle. A) 400 J, 100% B) 600 J, 66.67% C) 400 J, 66.67% D) 600 J, 100%

 [c] Heat of cycle = Net heat $=600-200=400\text{ }J$ Efficiency $\eta =\frac{\text{Work}\,\text{done}}{\text{Heat}\,\text{supplied}}=\frac{400}{600}$ $=66.67%$