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JEE Main & Advanced Physics Thermodynamical Processes Sample Paper Topic Test - Thermodynamical Processes

  • question_answer
    For a cyclic process \[A\to B\to C\to A,\] the following information is given
    Path \[\Delta Q\](Heat supplied) \[\Delta U\] (Increase in internal energy) Work done by system on surrounding
    \[A\to B\] 600 J 200 J 400 J
    \[B\to C\] - 100 J 100 J - 200 J
    \[C\to A\] - 100 J - 300 J 200 J
    Calculate the heat of the cycle and efficiency of cycle.

    A) 400 J, 100%

    B) 600 J, 66.67%

    C) 400 J, 66.67%

    D) 600 J, 100%

    Correct Answer: C

    Solution :

    [c] Heat of cycle = Net heat
                            \[=600-200=400\text{ }J\]
                Efficiency \[\eta =\frac{\text{Work}\,\text{done}}{\text{Heat}\,\text{supplied}}=\frac{400}{600}\]
                            \[=66.67%\]


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