A) 2/7
B) 7/2
C) 9/2
D) 2/9
Correct Answer: B
Solution :
[b] There is no heat flow through AB. Hence \[{{\theta }_{B}}={{20}^{o}}C\,{{H}_{DB}}={{H}_{BC}}\] |
\[\therefore \] \[\frac{(90-20)}{{{l}_{BD}}/KA}=\frac{(20-0)}{{{l}_{BC}}/KA}\] |
\[\therefore \] \[\frac{{{l}_{BD}}}{{{l}_{BC}}}=\frac{7}{2}\] |
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