A) \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{\rho }_{1}}{{s}_{1}}}{{{\rho }_{2}}{{s}_{2}}}\]
B) \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{\rho }_{1}}{{s}_{2}}}{{{\rho }_{2}}{{s}_{1}}}\]
C) \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{\theta }_{1}}}{{{\theta }_{2}}}\]
D) \[{{K}_{1}}={{K}_{2}}\]
Correct Answer: D
Solution :
[d] Rate of heat flow is, \[H=\frac{KA({{\theta }_{1}}-{{\theta }_{2}})}{\ell }\] |
For 1st rod \[{{H}_{1}}=\frac{{{K}_{1}}A({{\theta }_{1}}-{{\theta }_{2}})}{\ell }\] |
For 2nd rod \[{{H}_{2}}=\frac{{{K}_{2}}A({{\theta }_{1}}-{{\theta }_{2}})}{\ell }\] |
For \[{{H}_{1}}={{H}_{2}},{{K}_{1}}={{K}_{2}}\] |
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