A) \[120{}^\circ C\]
B) \[30{}^\circ C\]
C) \[40{}^\circ C\]
D) \[60{}^\circ C\]
Correct Answer: D
Solution :
[d] \[mS\left( \frac{dT}{dt} \right)\,=\,ka\,A\,({{\theta }_{in}}-{{\theta }_{out}})\] |
at heater at the wall |
\[k\,(\theta -20)=k'\,A\,(20+20)\] |
\[k\,(\theta -10)=k'\,A\,(10+40)\] |
\[\frac{\theta -20}{\theta -10}=\frac{40}{50}\] |
\[5\theta -100=4\theta -4\theta \] |
\[\theta =60{}^\circ C\] |
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