A) \[{{80}^{o}}C\]
B) \[{{60}^{o}}C\]
C) \[{{40}^{o}}C\]
D) \[{{70}^{o}}C\]
Correct Answer: B
Solution :
[b] \[\frac{100-0}{5/6R}=\frac{100-T}{R/3}\] \[\Rightarrow \] \[\frac{100\times 6}{5R}=\frac{(100-T)3}{R}\] \[\Rightarrow \] \[40=100-T\] \[\Rightarrow \] \[T={{60}^{o}}C\]You need to login to perform this action.
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