A) 605.3 m
B) 600 m
C) 80 m
D) 230 m
Correct Answer: A
Solution :
[a] The horizontal distance covered by bomb, \[BC={{v}_{H}}\times \sqrt{\frac{2h}{g}}=150\sqrt{\frac{2\times 80}{10}}=660m\] \[\therefore \] The distance of target from dropping point of bomb, \[AC=\sqrt{A{{B}^{2}}+B{{C}^{2}}}=\sqrt{{{(80)}^{2}}+{{(600)}^{2}}}=605.3\,m\]You need to login to perform this action.
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