A) Remain the same
B) Be doubled
C) Be quadrupled
D) Be halved
Correct Answer: C
Solution :
[c] \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\,\,\therefore \,\,H\propto {{u}^{2}}.\]If initial velocity be doubled then maximum height reached by the projectile will quadrupled.
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