A) 1.5 km
B) 3.0 km
C) 6.0 km
D) 0.75 km
Correct Answer: B
Solution :
[b] \[{{R}_{15{}^\circ }}=\frac{{{u}^{2}}\sin (2\times 15{}^\circ )}{g}\]\[=\frac{{{u}^{2}}}{2g}=1.5\,km\] \[{{R}_{45{}^\circ }}=\frac{{{u}^{2}}\sin (2\times 45{}^\circ )}{g}=\frac{{{u}^{2}}}{g}=1.5\times 2=3\,km\]You need to login to perform this action.
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