A) Zero
B) \[\frac{E}{2}\]
C) \[\frac{E}{\sqrt{2}}\]
D) \[E\]
Correct Answer: B
Solution :
[b] \[E'=E{{\cos }^{2}}\theta =E{{\cos }^{2}}(45{}^\circ )=\frac{E}{2}\]You need to login to perform this action.
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