2. Sample Papers
  3. JEE Main & Advanced
  4. Physics
  5. Two Dimensional Motion

JEE Main & Advanced Physics Two Dimensional Motion Sample Paper Topic Test - Two Dimensional Motion

  • question_answer
    The height \[y\] and the distance \[x\] along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by \[y=(8t-5{{t}^{2}})\] meter and \[x=6t\] meter, where \[t\] is in second. The velocity with which the projectile is projected is   

    A) 8 m/sec

    B) 6 m/sec

    C) 10 m/sec

    D) Not obtainable from the data

    Correct Answer: C

    Solution :

    [c] \[{{v}_{y}}=\frac{dy}{dt}=8-10t\], \[{{v}_{x}}=\frac{dx}{dt}=6\] at the time of projection i.e. \[{{v}_{y}}=\frac{dy}{dt}=8\]and \[{{v}_{x}}=6\] \[\therefore v=\sqrt{v_{x}^{2}+v_{y}^{2}}=\sqrt{{{6}^{2}}+{{8}^{2}}}=10\ m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner