JEE Main & Advanced Physics Two Dimensional Motion Sample Paper Topic Test - Two Dimensional Motion

  • question_answer
    Referring to above question, the angle with the horizontal at which the projectile was projected is

    A) \[{{\tan }^{-1}}(3/4\])

    B) \[{{\tan }^{-1}}(4/3)\]

    C) \[{{\sin }^{-1}}(3/4\])

    D) Not obtainable from the given data

    Correct Answer: B

    Solution :

    [b] The angle of projection is given by \[\theta ={{\tan }^{-1}}\left( \frac{{{v}_{y}}}{{{v}_{x}}} \right)={{\tan }^{-1}}\left( \frac{4}{3} \right)\]

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