A) 6000 \[\mu C\]
B) 1200\[\mu C\]
C) 12000\[\mu C\]
D) 6000\[\mu C\]
Correct Answer: A
Solution :
The circuit diagram of the set up is as shown. Equivalent capacitance in series is \[\frac{1}{C}=\frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}}\] \[=\frac{1}{4}+\frac{1}{6}=\frac{5}{12}\] \[\Rightarrow \] \[C=\frac{12}{5}\mu F\] Also, charge = capacitance \[\times \] voltage \[Q=\left( \frac{12}{5}\times 500 \right)\mu C\] \[Q=1200\,\mu C\]You need to login to perform this action.
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