A) \[C{{H}_{4}}N\]
B) \[{{C}_{2}}{{H}_{5}}N\]
C) \[C{{H}_{2}}N\]
D) \[C{{H}_{4}}{{N}_{2}}\]
Correct Answer: A
Solution :
Element | Percent | At. mass | Relative number of moles | Simple ratio |
C | 40 | 12 | \[\frac{40}{12}=3.3\] | \[\frac{3.3}{3.3}=1\] |
H | 13.3 | 1 | \[\frac{13.3}{1}=13.3\] | \[\frac{13.3}{3.3}\simeq 4.0\] |
N, | 46.67 | 14 | \[\frac{46.67}{14}=3.3\] | \[\frac{3.3}{3.3}=1\] |
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