A) 2486 Hz
B) 2132 Hz
C) 2068 Hz
D) 1950 Hz
Correct Answer: C
Solution :
Key Idea: Movement of the source and observer alters the wavelength and the received frequency of sound. As both source and observer are moving away, so observed frequency decreases. \[\therefore \] \[{{f}_{observed}}=\left( \frac{v-{{v}_{o}}}{v+{{v}_{s}}} \right){{f}_{s}}\] where, v is velocity of sound = 340 m/s Here, \[{{v}_{o}}=10\,m/s,\,{{v}_{s}}=10\,m/s\] \[\therefore \] \[1950=\left( \frac{340-10}{340+10} \right)\times {{f}_{s}}\] \[f\approx 2068\,Hz.\]You need to login to perform this action.
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