A) \[0.002\text{ }kg-{{m}^{2}}\]
B) \[0.02\text{ }kg-{{m}^{2}}\]
C) \[2\text{ }kg-{{m}^{2}}\]
D) \[0.2\text{ }kg-{{m}^{2}}\]
Correct Answer: D
Solution :
Key Idea: We have to find the moment of inertia of disc about its central axis in perpendicular plane. If the mass of a disc is M, its radius is R, then its moment of inertia about an axis passing through its centre of mass and perpendicular to its plane is \[I=\frac{1}{2}M{{R}^{2}}\] Given, \[M=0.4\,\]\[kg,R=100\,cm=1\,m\] \[\therefore \] \[I=\frac{1}{2}\times 0.4\times {{1}^{2}}=0.2\,\text{kg}-{{\text{m}}^{\text{2}}}\]You need to login to perform this action.
You will be redirected in
3 sec