A) 8.32 kJ
B) 12.36 kJ
C) 16.25 kJ
D) 20.74 kJ
Correct Answer: C
Solution :
Combustion of benzene can be represented as follows \[{{C}_{6}}{{H}_{6}}+{{O}_{2}}\xrightarrow{{}}6C{{O}_{2}}+{{H}_{2}}O+3250\,kJ\] 78 g of \[{{C}_{6}}{{H}_{6}}\]produce 3250 kJ heat 1 g will produce \[\frac{3250}{78}\]kJ heat 39 g will produce \[=\frac{3250}{78}\times 0.39\,\text{kJ}\] NOTE: Enthalpy of combustion is the amount of heat liberated when one mole of a substance is burnt in excess of air.You need to login to perform this action.
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