A) 6.8 L
B) 10.44 L
C) 11.2 L
D) 14.56 L
Correct Answer: C
Solution :
1 mole \[{{H}_{2}}=2\,g\,{{H}_{2}}=22.4\,L\,\]at STP \[\Rightarrow \] 1 g \[{{H}_{2}}=\frac{22.4}{2}=11.2L\]at STPYou need to login to perform this action.
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