A) 5.854
B) 6.7432
C) 8.8462
D) 8.0125
Correct Answer: D
Solution :
\[PV=\frac{w}{M}RT\] Let V be the volume occupied \[P=750\,mm=\frac{750}{760}\,atm\] \[V=?\] \[w=9\,g,\,T=300\,K\] \[V=\frac{wRT}{MP}=\frac{9\times 0.082\times 300\times 760}{28\times 750}=8.0125\,L\]You need to login to perform this action.
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