A) \[M\sqrt{\frac{Gm}{{{R}_{0}}}}\]
B) \[m\sqrt{\frac{GM}{{{R}_{0}}}}\]
C) \[M\sqrt{Gm{{R}_{0}}}\]
D) \[m\sqrt{GM{{R}_{0}}}\]
Correct Answer: D
Solution :
Angular momentum of satellite \[L=mvR\] where v is orbital velocity of satellite and R is radius of earth. Orbital velocity of satellite \[v=\sqrt{\frac{GM}{R}}=\sqrt{\frac{GM}{{{R}_{0}}}}\] (Here, \[R={{R}_{0}}\]) Hence, angular momentum \[L=m\sqrt{\frac{GM}{{{R}_{0}}}}{{R}_{0}}=m\sqrt{GM{{R}_{0}}}\]
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