A) 1
B) 2
C) 4
D) 6
Correct Answer: A
Solution :
Key Idea: Emission of one P -particle increases the atomic number by 1 unit. The given reaction can be shown as \[_{90}{{X}^{238}}{{\to }_{83}}{{Y}^{222}}\] Change in mass number \[=238-222=16\] If original nucleus decays an \[\alpha -\]particle it will reduce the initial mass by 4 unit and atomic number by 2 unit. So, \[\alpha -\]pariticles emitted \[=\frac{16}{4}=4\] Change in atomic number\[~=90-2\times 4=\text{ }82\] But on emission of one \[\beta -\]particle, there is always an increase in atomic number by 1 . So, no. of \[\beta -\]particles = 83 - 82 = 1
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