A) 121
B) 195
C) 126
D) 103
Correct Answer: C
Solution :
Method used to form the series is \[{{\left( 1 \right)}^{3}}+1,{{\left( 2 \right)}^{3}}+1,{{\left( 3 \right)}^{3}}+1,{{\left( 4 \right)}^{3}}+1,.......\] Therefore, the missing number is \[{{\left( 5 \right)}^{3}}+1=126\]
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