A) \[6.626\times {{10}^{-35}}m\]
B) \[6.626\times {{10}^{-33}}m\]
C) \[6.626\times {{10}^{-34}}m\]
D) None of these
Correct Answer: A
Solution :
For wavelength \[\lambda \]and momentum \[(p=\,mv)\] from de-Broglie concept, \[\lambda =\frac{h}{p}=\frac{h}{mv}\]where h is Planck's canstant. \[\therefore \] \[\lambda =\frac{6.626\times {{10}^{-34}}}{1\times 10}\approx 6.626\times {{10}^{-35}}\,\text{m}\]
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