AFMC AFMC Solved Paper-2001

  • question_answer
    The reactance of a coil when used in the AC power supply (220 V, 50 cycle/s) is 50 ii. The inductance of the coil is nearly :            

    A) 0.16 H                                   

    B) 0.22 H           

    C) 2.2 H                                     

    D) 1.6 H

    Correct Answer: A

    Solution :

    In a coil the product of angular frequency \[(\omega )\] and inductance (L) is known as the reactance of the coil or inductive reactance and is denoted by \[{{X}_{L}}.\] Thus,     \[{{X}_{L}}=\omega L=2\pi fL\]where\[f\]is frequency. Putting the numerical values from the question, we have \[{{X}_{L}}=50\Omega ,\,\,f=50\,cps\] \[\therefore \]   \[L=\frac{{{X}_{L}}}{\omega }=\frac{{{X}_{L}}}{2\pi f}=\frac{50}{2\pi \times 50}=\frac{1}{2\times 3.14}=0.16\,H.\]


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