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AFMC AFMC Solved Paper-2001

  • question_answer
    The energy of ground electronic state of hydrogen atom is -13.6 eV. The energy of the first excited state will be :

    A) -52,4eV                               

    B) -27.2eV

    C) -68eV                                   

    D) -3.4 eV

    Correct Answer: D

    Solution :

    The energy of \[{{n}^{th}}\]excited state is given by \[{{E}_{n}}=-\frac{13.6}{{{n}^{2}}}\] For first excited state, n = 2 \[\therefore \]             \[{{E}_{n}}=-\frac{13.6}{4}=-3.4eV\]


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