A) \[\frac{{{m}_{1}}{{m}_{2}}g}{{{m}_{1}}-{{m}_{2}}}\]
B) \[\frac{{{m}_{2}}g}{{{m}_{1}}+{{m}_{2}}}\]
C) \[\frac{{{m}_{1}}g}{{{m}_{1}}+{{m}_{2}}}\]
D) \[g\]
Correct Answer: B
Solution :
Key Idea: Force acting on block which causes acceleration is F = ma. The free body diagram depicting the situation is shown. Resultant force acting on hanging block is \[({{m}_{2}}g-T).\] Force acting on block \[{{m}_{2}}\]which causes acceleration is \[{{m}_{2}}a\] Hence, \[{{m}_{2}}g-T={{m}_{2}}a\] ?(i) Also, \[T={{m}_{1}}a\] ?(ii) From Eqs. (i) and (ii), we get \[a=\frac{{{m}_{2}}g}{{{m}_{1}}+{{m}_{2}}}\]You need to login to perform this action.
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