A) \[120{}^\circ\]
B) \[90{}^\circ\]
C) \[180{}^\circ\]
D) zero
Correct Answer: B
Solution :
Key Idea: Cosine expression can be expressed in terms of sine expression using identity \[\sin (\pi /2+\theta )=cos\theta .\] The given displacement equations are \[{{y}_{1}}=a\cos \omega t\] \[{{y}_{1}}=a\sin \left( \omega t+\frac{\pi }{2} \right)\] ?(i) and \[{{y}_{2}}=a\sin \omega t\] Hence, phase difference between \[{{y}_{1}}\]and \[{{y}_{2}}\] Hence, phase difference is \[{{90}^{o}}.\]You need to login to perform this action.
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