A) + 294.4 kJ
B) - 294.4 kJ
C) + 462.4 kJ
D) - 462.4 kJ
Correct Answer: B
Solution :
Sulphur bums in oxygen according to the following equation \[\underset{32g}{\mathop{S}}\,+{{O}_{2}}\xrightarrow{{}}S{{O}_{2}}+\Delta {{h}_{f}}\] 0.5 g S liberate = 4.6 kJ heat 1 g S liberate \[=\frac{4.6}{0.5}kJ\] 32 g s will liberate \[=\frac{4.6}{0.5}\times 32=294.4kJ\] Heat of formation is the amount of heat liberated or absorbed when one mole of compound is formed from its constituent elements hence, Heat of formation of \[S{{O}_{2}}=-294.4\,kJ\]
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