A) 6.0V
B) 40V
C) 3.4V
D) 25V
Correct Answer: D
Solution :
Key Idea: In parallel combination of resistances the potential difference between the ends is same. The two resistances \[40\Omega \]and \[60\Omega \] are connected in parallel, since their first ends are connected to one point and second ends to the other. \[\therefore \] \[\frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}\] \[=\frac{1}{60}+\frac{1}{40}\] \[\Rightarrow \] \[R=24\,\Omega \] In this circuit, the current is \[\Rightarrow \] \[i=\frac{E}{R}=\frac{6}{24}A\] Hence, potential difference across voltmeter is \[V=iR'\] \[=\frac{6}{24}\times 100=25\text{V}\]You need to login to perform this action.
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