A) 3
B) 4
C) 2
D) 1
Correct Answer: D
Solution :
\[\text{HCl}\]is a strong acid hence, it is 100% under all concentrations. \[[{{H}_{3}}{{O}^{+}}]\]of \[\frac{N}{10}HCl=\frac{1}{10}={{10}^{-1}}M\] \[pH=-\log [{{H}_{3}}{{O}^{+}}]\] \[=-\log ({{10}^{-1}})=1\]
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