A) \[0.576\times {{10}^{-8}}\,mol/L\]
B) \[1.056\times {{10}^{-4}}mol/L\]
C) \[1.249\times {{10}^{-5}}L\]
D) \[1.478\times {{10}^{-6}}mol/L\]
Correct Answer: C
Solution :
\[\text{AgCl}\]is a sparingly soluble salt. Let its solubility be s mol/L. \[AgCl\underset{s}{\mathop{A{{g}^{+}}}}\,+\underset{s}{\mathop{C{{l}^{-}}}}\,\] Solubility product \[{{K}_{sp}}\] \[{{K}_{sp}}=s\times s\] \[s=\sqrt{{{K}_{sp}}}=\sqrt{1.56\times {{10}^{-10}}}\] \[s=1.249\times {{10}^{-5}}\,mol/L\]
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