A) low temperature, high pressure and catalyst
B) high temperature, high pressure and catalyst
C) high temperature, high pressure and catalyst
D) low temperature, low pressure and catalyst
Correct Answer: A
Solution :
\[\underset{4V}{\mathop{{{N}_{2}}(g)}}\,+\underset{3V}{\mathop{3{{H}_{2}}(g)}}\,\]\[\underset{2V}{\mathop{2N{{H}_{3}}}}\,(g)21.9\,kcal\] The above reaction is exothermic reaction and the moles of reactants are more than moles of products. According to Le-Chatelier's principle, the conditions favourable for formation of \[\text{N}{{\text{H}}_{\text{3}}}\]are \[\to \]Low temperature \[\to \]High pressure and presence of catalyst
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