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AFMC AFMC Solved Paper-2001

  • question_answer
    4 g caustic soda is dissolved in 100 cc of solution. The normality of solution is:

    A) 0                                             

    B) 0.5 

    C) 1                                             

    D) 1.5

    Correct Answer: C

    Solution :

    Normality is defined as number of equivalents of a substance present in 1 L of solution \[N=\frac{gram\,equivalents\,of\,solute}{volume\,(L)}\] \[=\frac{mass\,of\,solute\,(g)}{equivalent\,mass\,of\,solute\,\times vol\,(L)}\] \[N=\frac{4}{40}\times \frac{1}{0.1}=1N\]


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