A) Faraday
B) Ostwald
C) Arrhenius
D) Lamarck
Correct Answer: A
Solution :
Faraday gave the laws of electrolysis I law : Mass of a substance liberated at cathode is directly proportional to quantity of electricity passed, \[m\propto Q\,\,\,Q=amount\,of\,ch\arg e\] Or m = zit i = current (amp) t = time (sec) Z = electrochemical equivalent II law: When same amount of electricity is passed through different electrolytes connected in sepes then the masses of the substances liberated at the electrodes are in the ratio of their equivalent mass \[\frac{m{{ & }_{1}}}{{{m}_{2}}}=\frac{{{(eq.mass)}_{1}}}{{{(eq.mass)}_{2}}}=\frac{{{Z}_{1}}}{{{Z}_{2}}}\]
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