A) 0.71
B) 0.61
C) 0.31
D) 0.81
Correct Answer: B
Solution :
Key Idea: Centripetal force is provided by the frictional force between the tyres and the road. A body performing a circular motion is acted upon by a force which is always directed towards the centre of the circle, This force is called Centripetal centripetal force. If m is mass, v is velocity, r is radius then \[F=\frac{m{{v}^{2}}}{r}\] Also when the cyclist takes a turn on the road, the centripetal force is provided by the frictional force between the tyres and road. \[\therefore \] \[F=\mu mg\] ?(ii) Equating Eqs. (i) and (ii), we get \[\mu =\frac{{{v}^{2}}}{rg}\] Putting the numerical values from the question, we have \[\therefore \] \[\mu =\frac{{{(4.9)}^{2}}}{4\times 9.8}=0.61\]
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