A) 400 V
B) 300 V
C) 200 V
D) 100 V
Correct Answer: A
Solution :
The capacitance (C) of a conductor is defined as the ratio of charge (q) given to the rise in the potential (V) of the conductor\[C=\frac{q}{V}\]Equivalent capacitance of the capacitors joined in parallel is \[C={{C}_{1}}+{{C}_{2}}\] The common potential is given by \[V=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\] Putting the numerical values, we get \[V=\frac{20\times {{10}^{-6}}\times 500+10\times {{10}^{-6}}\times 200}{(20+10)\times {{10}^{-6}}}\] \[V=\frac{12000}{30}=400\,\,V\]You need to login to perform this action.
You will be redirected in
3 sec