A) 4 days
B) 6 days
C) 15 days
D) 18 days
Correct Answer: C
Solution :
\[\because \,x\,and\,y\]can do a piece of work in 6 days, then\[\left( x+y \right)'s\] one day work = \[\frac{1}{6}th\,part\] and\[x\] alone can do the same work in 10 days and \[\text{A }\!\!'\!\!\text{ s}\] one day work = \[\frac{1}{10}th\,part.\] Now B's one day work =\[\frac{1}{6}-\frac{1}{10}\] \[=\frac{5-3}{30}=\frac{2}{30}=\frac{1}{15}\]You need to login to perform this action.
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