A) 8\[\mu \]F
B) 6\[\mu \]F
C) 4\[\mu \]F
D) 2\[\mu \]F
Correct Answer: C
Solution :
Key Idea: The setup is a balanced Wheat stones, bridge. The ratio of capacitances in the opposite arms is same, hence it is a balanced Wheatstone bridge. Therefore, middle capacitor becomes ineffective. For resultant capacitance in seriesYou need to login to perform this action.
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