AFMC AFMC Solved Paper-2002

  • question_answer
    If the equation of a sound wave is given as y = 0.0015 sin (62.8.v + 316t), then wave length of this wave is:

    A) 0.1 unit                                

    B) 0.2 unit

    C) 0-4 unit                

    D) 0.5 unit

    Correct Answer: A

    Solution :

    Key Idea: Standard equation of progressive  sound wave is \[y=a\sin 2\pi \left( \frac{t}{T}+\frac{x}{\lambda } \right)\] For a wave travelling with amplitude a,  wavelength\[\lambda \]having periodic time T,  the displacement equation at instant t is given by \[y=a\sin 2\pi \left( \frac{t}{T}+\frac{x}{\lambda } \right)\]          ?(i) Given, equation of wave is \[y=0.0015\sin (62.8x+316t)\]              ?(ii) Comparing Eqs. (i) and (ii), we get \[\frac{2\pi x}{\lambda }=62.8x\] \[\Rightarrow \]   \[\lambda =\frac{2\pi }{62.8}=0.1\,\text{unit}\]


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