A) 40 kN
B) 30 kN
C) 20 kN
D) 10 RN
Correct Answer: D
Solution :
Key Idea: Average resistance offered by the target to the bullet is given by Newton's second law. From equation of motion we have\[{{v}^{2}}={{u}^{2}}-2\,as\] where, v is final velocity, u is initial velocity, a is acceleration and s is displacement Given, \[u=200\,m/s,\,s=0.05\,m,\,v=0\] \[\therefore \] \[O={{(200)}^{2}}-2a\times 0.05\] \[\Rightarrow \] \[a=\frac{{{(200)}^{2}}}{2\times 0.5}=4\times {{10}^{4}}\,m/{{s}^{2}}\] Resistance offered = F = ma \[=0.25\times 4\times {{10}^{4}}\] \[=10\times {{10}^{3}}N=10\text{kN}\]
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