A) 4.4673 kJ
B) 3.857 kJ
C) 2.493 kJ
D) 1.857 kJ
Correct Answer: C
Solution :
\[KE=\frac{3}{2}nRT=\frac{3}{2}.\frac{W}{M}.RT\](Mol. mass of N = 28) \[=\frac{3}{2}\times \frac{14}{28}\times 8.31\times 400\] \[[T=273+127=400K]\] \[=2493\,\,J\]or 2.493 kJYou need to login to perform this action.
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