A) 185 W
B) 100 W
C) 54 W
D) 64 W
Correct Answer: D
Solution :
Key Idea: Power is dissipated in inverse proportion of resistance. Power dissipated is given by \[P=\frac{{{V}^{2}}}{R}\] \[\Rightarrow \] \[R=\frac{{{V}^{2}}}{P}\] Putting the numerical values, we have \[R=\frac{{{(200)}^{2}}}{100}=400\Omega \] Supply voltage \[{{V}_{s}}=160V\] Actual power consumption is given by \[P=\frac{V_{s}^{2}}{R}=\frac{{{(160)}^{2}}}{400}=64\,W\]You need to login to perform this action.
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